Question

3x-4y=7;5x+2y=3 elimination method​

Answer 1

Answer:

3x - 4y = 5 equation 1

5x + 2y =3 equation 2

Multipying equation 1 by 2 and equation 2 by 4.

let's add equation 1 and 2

3x - 4y = 5 × 2

5x +2y = 3 × 4

= 6x - 8y = 10

20x + 8y = 12

= 26 = 22

Answer is not given so it's wrong question.

Answer 2

Answer:

Step-by-step explanation:

for 'X'

3x-4y=7 ... ( equation 1)

5x+2y=3 ... ( equation 2)

(x) 2nd equation with 2

(2)5x + (2)2y = (2)3

10x + 4y = 6 ... (equation 3)

(add) equation 1 and 3

3x-4y=7

10x+4y=6

13x = 1

x = 1/ 13

x= .07

FOR 'Y'

(x) 1st equation with 5 and 2nd with 3

3x-4y=7 (5)

5x+2y=3 (3)

15x - 20y = 35 ... (equation 4)

15x + 6y =  9 ... (equation 5)

(subtract both 4 and 5th equation)

___( in subtraction; signs of the second equation changes)___

15x - 20y = 35

- 15x - 6y = - 9

-26y = 26

y = -1