3x-4y=7 and 5x+2y=3 substitution method
find the value of 7x+5y
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2
3x=7-4y
x=7-4y/3. put value in 2nd eqn.
5(7-4y)/3+2y=3
35+26y=9
y=-1. put value in 1st eqn.
3x+4=7
x=1
7x+5y= 7×1+5×-1. =7-5. = 2. Ans.
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