Question

|3x-5/2|_>2 solve it in modules. form​

Answer 1

| (3x - 5)/2 | ≥ 2

| (3x - 5) | / 2 ≥ 4

| (3x - 5) | ≥ 4

Case 1:

==> 3x - 5 ≥ 4

==> 3x ≥ 9

==> x ≥ 3 ...(1)

Case 2:

==> -3x + 5 ≤ -4

==> 3x ≥ 9

==> x ≥ 3 ...(2)

Hence, From (1) and (2)

x ∈ [3, ∞)