Question

(3x/5)-(2x-1/3)>1. If x€W find the solution set and represent on numbers line

Answer 1

$\frac{3x}{5} - \frac{2x - 1}{3} > 1 \\ \frac{9x - 5(2x - 1)}{15} > 1 \\ \frac{9x - 10x + 5}{15} > 1 \\ \frac{ - x + 5}{15} > 1 \\ - x + 5 > 15 \\ - x > 15 - 5 \\ - x > 10 \\ x < - 10$

Answer 2

Given

• (3x/5)-((2x-1)/3)>1
• x€W

To find

• solution set and represent on numbers line

Solution

we are provided and inequality and I asked it to find the value or solution set for x that is the range of values for x for which the inquality will hold.

3x/5 - (2x-1)/3 > 1

or, 【9x - 5(2x-1)】/15 >1 ( taking LCM)

or, 【9x-10x+5】/15 >1

or, (-x+5) > 15

or, -x > 10 ( bringing 5 left)

therefore, x would be less than negative 10