Question

3x + 5 4x + 2 - 3x +4 4x +7​

Answer 1

Answer:

We have, (3x + 5)/ (4x + 2) = (3x + 4)/(4x + 7) (3x + 5)/ (4x + 2) – (3x + 4)/(4x + 7) = 0 By taking LCM as (4x + 2) (4x + 7) ((3x + 5) (4x + 7) – (3x + 4) (4x + 2)) / (4x + 2) (4x + 7) = 0

By cross-multiplying we get, (3x + 5) (4x + 7) – (3x + 4) (4x + 2) = 0 (3x + 5) (4x + 7) – (3x + 4) (4x + 2) = 0 12x2 + 21x + 20x + 35 – 12x2 – 6x – 16x – 8 = 0 19x + 35 – 8 = 0 19x = -27 x = -27/19

Now let us verify the given equation, (3x + 5)/ (4x + 2) = (3x + 4)/(4x + 7) By substituting the value of ‘x’ we get, (3(-27/19) +5) / (4(-27/19) + 2) = (3(-27/19) + 4) / (4(-27/19) + 7) (-81/19 + 5) / (-108/19 + 2) = (-81/19 + 4) / (-108/19 + 7) ((-81+95)/19) / ((-108+38)/19) = ((-81+76)/19) / ((-108+133)/19) 14/19 / -70/19 = -5/19 / 25/19 -14/70 = -5/25 -1/5 = -1/5

Hence, the given equation is verified.

Answer 2

Answer:

Given *(3x+5)/(4x+2)=(3x+4)/(4x+7); =>(4x+7)(3x+5)=(3x+4)(4x+2); =>12x^ ^ 2+20x+21x+35=12x^ ^ 2+6x+; 16x + 8; =>12x^ 4 2+20x+21x-12x^ 4 2-6x-16x=; 8 - 35; =>20x+21x-22x=-27; =>19x=-27; =>x=-27/19 Hope this helps!