Question

3x-5 find integration​

Answer 1

Answer:

5/3

Explanation:

3x -5 = 0

3x = 5

x = 5/3

Thank you

Answer 2

Answer: $\rm \dfrac{3x^2}{2} + 5x + C$

Explanation:

$\rm \int 3x + 5$

= $\rm \int 3x \ dx + \int 5 \ dx$

= $\rm 3 \int x \ dx + 5 \int x^0 \ dx$

(Constants are removed.)

= $\rm 3 \dfrac{x^{1+1}}{1+1} + 5 \dfrac{x^{0+1}}{0 + 1} + C$

[n ≠ 1.]

= $\rm \dfrac{3x^2}{2} + 5x + C$.

More: If we differentiate the last expression, we will end up with the first expression, i.e., 3x + 5.

Use,

$\rm \dfrac{d}{dx}(x^n) = nx^{(n - 1)}$.