3x/5=(x^2+8)/10 solve for equation
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3x/5=(x^2+8)/10
⇒x²-6x+8=0
⇒x²-4x-2x+4*2=0
⇒(x-4)(x-2)=0
⇒x=2 or 4 is solution to given equation
rohitkush432pe9zjw:
but how -6x comes
here 5*2 =10 so denominators get canceled resulting in 3*2x on cross multiplication
thanks
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