3x - 5 y= 11 , 7x -2y = 11
linear equations in two variables
Answers
Required solution...
We have to draw graphs of expressions of linear equation in two variables: 3x - 5y = 11, 7x - 2y = 11
~ Firstly let's assume that
- 3x - 5y = 11 is equation 1
- 7x - 2y = 11 is equation 2
~ Now let's put x as 0 in equation 1
→ 3x - 5y = 11
→ 3(0) - 5y = 11
→ 0 - 5y = 11
→ -5y = 11
→ y = 11/-5
→ y = -2.2
- We get coordinates as (0,-2.2)
~ Now let's put y as 0 in equation 1
→ 3x - 5y = 11
→ 3x - 5(0) = 11
→ 3x - 0 = 11
→ 3x = 11
→ x = 11/3
→ x = 3.66
→ x ≈ 3.7
- We get coordinates as (3.7,0)
~ Now let's put x as 0 in equation 2
→ 7x - 2y = 11
→ 7(0) - 2y = 11
→ 0 - 2y = 11
→ -2y = 11
→ y = 11/-2
→ y = -5.2
- We get coordinates as (0,-5.2)
~ Now let's put y as 0 in equation 2
→ 7x - 2y = 11
→ 7x - 2(0) = 11
→ 7x - 0 = 11
→ 7x = 11
→ x = 11/7
→ x = 1.5
- We get (1.5,0) as coordinate
They intersect at (1.1,-1.5)
Extra information...
The system used for describing the position of a point in the plane is known as cartesian system.
Relation between the signs of the coordinates of a point and the quadrant of a point in which it lie.
1) If the point is in the first quadrant then the point will be in the form of (+,+) since the 1st quadrant is enclosed by the positive x-axis and positive y-axis
2) If the point is in the second quadrant then the point will be in the form of (-,+) since the 2nd quadrant is enclosed by the negative x-axis and positive y-axis
3) If the point is in the third quadrant then the point will be in the form of (-,-) since the 3rd quadrant is enclosed by the negative x-axis and negative y-axis
4) If the point is in the fourth quadrant then the point will be in the form of (+,-) since the 4th quadrant is enclosed by the positive x-axis and negative y-axis
- Kindly see this concept from attachment 4th
