Question

3x - 5x^2 + 12 has maximum value at x is​

Answer 1

Step-by-step explanation:

We have,

$y = 3x - 5 {x}^{2} + 12$

To be maximum, its derivative will be equal to 0

so,

$\frac{dy}{dx} = 3 - 10x = 0$

$= > x = \frac{3}{10}$