Question

3x-5x=20,6x-10y=40(cross multiplication method)(chapter name:-pair of linear equations in two variables)​

Answer 1

Answer:

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Answer 2

Answer:

x=0, y=0

Step-by-step explanation:

3x-5y=20 => 3x-5y-20=0 => a1= 3, b1= -5, c1= -20

6x-10y=40 => 6x-10y-40=0 => a2= 6, b2= -10, c2= -40

x/b1c2 - b2c1 = y/c1a2 - c2a1 = 1/a1b2 - a2b1 =>

x/ -5*-40 -(-10*-20) = y/ -20*6 -(-40*3) = 1/3*-10-(6*-5) =>

x/200 - (200) = y/ -120-(-120) = 1/ -30-(-30) =>

x/0 = y/0 = 1/0 =>

x=0, y=0