3x-5y=-1 and x-y=-1 by cross multiplication method
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[3x - 5y = -1] × 1
[ x - y = -1] × 3
------------------------------
3x - 5y = -1
3x - 3y = -3
-__(+)__(+)
0-2y = 2
________
=> 2y = -2
=> y = -2/2
=> y = -1
Putting the value of y in x-y = -1
=> x -(-1) = -1
=> x+ 1 = -1
=> x = -1-1
=> x = -2
x = -2
y = -1
I hope this will help you
-by ABHAY
[ x - y = -1] × 3
------------------------------
3x - 5y = -1
3x - 3y = -3
-__(+)__(+)
0-2y = 2
________
=> 2y = -2
=> y = -2/2
=> y = -1
Putting the value of y in x-y = -1
=> x -(-1) = -1
=> x+ 1 = -1
=> x = -1-1
=> x = -2
x = -2
y = -1
I hope this will help you
-by ABHAY
sharu14:
lit fam
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