Question

3x+5y=12 4x+2y=5 by substitution by equating any one of the cofficients method​

Answer 1

Answer:

3x+5y=5

5y=12-3x

put x=0

5y=12-3 (0)

5y=12

y=12/5

(¡¡)4x+2y=5

2y=5-4x

put x=1

2y=5-4 (1)

2y=1

y=1/2