3X+5Y=12 5X+3Y=4 solve using substitution
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Answered by
2
Answer:
Step-by-step explanation: Here we have two equation
3x+5y=12. Eqn1
5x+3y=4. Eqn2
So , we multipy the eqn1 by 5 and eqn2 by 3
We get,
15x+25y=60 eqn 3
15x+9y=12. eqn4
By dividing eqn3/eqn4
We get
16y=48
y=3
And putting the value of y in eqn 1 we get,
3x+5(3)=12
3x+15=12
3x=-3
x=-1
Answered by
3
Answer:
Step By-step explanation
3X+5Y=12 ----- 1
5X+3Y=4 -----2
FROM EQUATION 2
X= 4 - 3Y/5
SUBSTITUTING THESE VALUE IN EQUATOIN 1
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