Question

3x-5y=12 and 4x-3y=13 solve the equation by elimination method

Answer 1

Answer:

Given,

3x-5y=12 ---------(1)

4x-3y=13 ---------(2)

By Elimination Method

x = $\frac {12-5y} {3}$ (from equation (1))

Put value of x in (2)

4 ($\frac {12-5y} {3}$) -3y = 13

$\frac {48-20y} {3}$ -3y = 13

48 - 20y - 9y = 39

-29y = 9

y = $\frac {-9} {29}$

and x = $\frac {393} {87}$

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