Question

3x-5y-19=0 and -7x+3y+1=0 solve using substitution methof

Answer 1

Answer:

3x - 5y-19=0

therefor

3x-5y =19 ......(1)

2nd equation is -7x+3y+1=0

-7x+3y=-1

get (-)to the both the side

7x -3y =1 .........(2)

x = (1+ 3y)/7

put this value of x in equation (1)

3((1+3y)/7)-5y =19

3 + 9y - 35y = 19 X 7

3 - 26 y = 133

-26y = 133-3

y= 130/-26

y = -5

substitute the value of y in equation in (1)

3x-5y =19

3x - 5(-5) =19

3x +25 = 19

3x = 19 -25

x = -6/3

x = -2

therefor the values of x and y are

$\boxed{\textbf{\large{x = -2}}}$

$\boxed{\textbf{\large{y=-5}}}$