Question

3x+5y=19. 5x+3y=21 solve this simultaneous equations

Answer 1

$3x + 5y = 19 \\ x = \frac{19 - 5y}{3}$
$5x + 3y = 21 \\ 5( \frac{19 - 5y}{3} ) + 3y = 21 \\ \frac{95 - 25y}{3 } + 3y = 21 \\ \frac{95 - 25y + 9y}{3 } = 21 \\ 95 - 16y = 63 \\ - 16y = 63 - 95 \\ - 16y = - 32 \\ y = \frac{ - 32}{ - 16 } \\ y = 2$
$putting \: eq \: (1) \\ 3x + 5y = 19 \\ 3x + 5 \times 2 = 19 \\ 3x = 19 - 10 \\ 3x = 9 \\ x = \frac{9}{3 } \\ x = 3ans$

Answer 2

Answer:

5x+3y apon 5x-3y =21 apon 17 find x apon y