Question

3x-5y=20, 6x-10y=40 elimination method​

Answer 1

hello good to see you

3x-5y=20 × 6

6x-10=40 × 3

I'm going to eliminate x

so we have to equal two x's

but the problem is we cant do this because two EQUATIONS are same when we equalize it

so iam going to do substitution method

$→3x−5y=20</p><p>→3x=20+5</p><p>→x=320+5y−−−−−(1)</p><p>→6x−10y=40puttingvalueofxin(2)</p><p>→6×(320+5y)−10y=40</p><p>→320+5y−30y=640</p><p>→20−25y=640×3</p><p>→20−25y=20</p><p>→−25y=20−20∴y=0puttingvalueofyin(1)</p><p>→x=320+5y</p><p>→x=320+5×0∴x=320</p><p></p><p>$