Question

3x-5y=20 ,6x-10y=40 solve with substitution method

Answer 1

Answer:

$\huge{\pink{\boxed{\green{\sf{\therefore x=\frac{20}{3}}}}}}$

$\huge{\pink{\boxed{\green{\sf{\therefore y=0}}}}}$

Step-by-step explanation:

$\huge{\pink{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}$

$\: \: \: \: { \orange{given}} \\{ \pink{ \boxed{ \green {3x - 5y = 20}}}} \\{ \pink{ \boxed{ \green {6x - 10y= 40}}}} \\ \\ { \blue{to \: find}} \\ {\purple{ \boxed{ \red {x = ?}}}} \\ {\purple{ \boxed{ \red {y =?}}}}$

☆ According to the given question:

☆ Using substitution method to solve this:

$\to 3x - 5y = 20 \\ \to 3x = 20 + 5y \\ \to x = \frac{2 0 + 5y }{3} - - - - - (1)\\ \\ \to 6x - 10y = 40\\ putting \: value \: of \: x \: in \: (2) \\ \to 6 \times (\frac{20 + 5y}{3} ) - 10y = 40 \\ \to \frac{20 + 5y - 30y}{3} = \frac{40}{6} \\ \to 20 - 25y = \frac{40}{6} \times 3 \\ \to 20 - 25y = 20 \\ \to - 25y = 20 - 20 \\ { \pink{ \boxed{ \green{\therefore y = 0}}}} \\ \\ putting \: value \: of \: y \: in(1) \\ \to x = \frac{20 + 5y}{3} \\ \to x = \frac{20 + 5 \times 0}{3} \\ { \pink{ \boxed{ \green{\therefore x = \frac{20}{3} }}}}$

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Answer 2

Step-by-step explanation:

System of Linear Equations entered :

  [1] 3x - 5y = 20   [2] 6x - 10y = -40

Solve by Substitution :

// Solve equation [2] for the variable  x 

 

[2] 6x = 10y - 40 [2] x = 5y/3 - 20/3

// Plug this in for variable  x  in equation [1]

  [1] 3•(5y/3-20/3) - 5y = 20   [1] 0 = 40 => NO solution