Question

3x-5y-4=0 ; 9x=2y-1 solve it in elimination method

Answer 1

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Solve it by elimination method: 3x-5y-4=0 ; 9x=2y-1

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$\boxed{\red{\bold{First \ equation:}}}$

$\red{\implies}3x-5y-4=0$

$\red{\implies}9x - 15y - 12 =0$

$\boxed{\red{\bold{Second \ equation;}}}$

$\blue{\implies}9x = 2y-1$

$\blue{\implies}9x-2y+1=0$

$\boxed{\red{\bold{Subtracting \ the \ equations:}}}$

$\begin{aligned}</p><p></p><p>9x-15y-12 & = 0 \\</p><p></p><p>9x-2y+1 & = 0 \\</p><p>- \; \; \; \; + \; \; \; \; \; - \\</p><p> -13y -13 & =0</p><p></p><p>\end{aligned}$

$-13y - 13 =0$

$y + 1 =0$

$\green{\boxed{\implies{\boxed{y = -1}}}}$

$\green{\boxed{\implies{\boxed{x = \displaystyle \frac{-1}{3}}}}}$

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