Question

3x-5y-4=0 &9x-2y=7 Solve by
elmination memod.​

Answer 1

Answer:

3x-5y-4=0

3x-5y=4

3x=4+5

3x=9

x=9/3

x=3

Step-by-step explanation:

9x-2y=7

2y=7+9

2y=16

y=16/2

y=8

It's not helpful for u

okk use ur own mind

with help of example

its icse or cbse

if u r icse I can help u okk

Answer 2

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

Elimination method is a way of eliminating one variable from equation of two variable so that we can find value of one variable.

Elimination means =>To Remove

Method step by step For Elimination Method :

step 1: Firstly Multiply with any non-zero value so that the coefficient of any one variable be equal and gets eliminated.

Generally we multiply with coefficient of a variable of both equation to each term.

step2: After Put negative sign where value is positive and put positive sign where value is negative so that any one variable gets eliminated or subtracted and hence we find value of any one variable.

step3: Now,after finding value of one variable substitute it another equation.

$\sf \longmapsto3x - 5y = 4 - ( \times 9)$

$\sf \longmapsto9x - 2y = 7 - ( \times 3)$

New Equation obtained:

27x - 45y = 36

27x - 6y = 21

$(-)$$\:\:(+)$$\:\:\:\:(-)$

______________

-39y=15

y=-15/39=-5/14

$\sf \bold{ y = - \dfrac{5}{13} }$

$\sf \longmapsto3x - 5y = 4$

$\sf \longmapsto3x - 5 \times - \dfrac{5}{13} = 4$

$\sf \longmapsto3x + \dfrac{25}{13} = 4$

$\sf \longmapsto3x = 4 - \dfrac{25}{13} = \dfrac{52 - 25}{13} = \dfrac{27}{13}$

$\sf \longmapsto3x = \dfrac{27}{13}$

$\sf \longmapsto \: x = \dfrac{27}{13} \times \dfrac{1}{3} = \dfrac{9}{13}$

$\sf \bold{x = \dfrac{9}{13} }$

Check

$\sf \longmapsto3x - 5y = 4$

$\sf \longmapsto3 \times \dfrac{9}{13} - 5 \times - \dfrac{5}{13}$

$\sf \longmapsto \dfrac{27}{13} + \dfrac{25}{13} = \dfrac{52}{13} = 4$