3x-5y-4=0 and 3x-2y-7=0
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Here,
3x - 5y -4 = 0
=> 3x = 4+ 5y
=> x = (4+ 5y)/3 ----(1)
now,
3x - 2y -7 = 0
[now putting the value of x from equation (1)]
=> 3 [(4+5y)/ 3] -2y = 7
=> 4+ 5y -2y = 7
=> 3y = 7-4
=> y = 3/3
=> y = 1
hence, putting the value of y in equation (1)
x = (4 + 5y) /3
= [ 4 + 5(1) ] /3
= (4 +5)/3
= 9/3
= 3
Therefore,
X = 3
Y = 1
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sumitkaushik291:
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