3x-5y-4=0 and 9x=2y+7 solve it with elimination method.
Answers
Answered by
826
(3x -5y=4)×2
(9x-2y= 7)×5
6x-10y=8
45-10y= 35
now , subtract.
so , we get
39x= 27
x = 27/39 = 9/13
so , y = -5/13 ans.
(9x-2y= 7)×5
6x-10y=8
45-10y= 35
now , subtract.
so , we get
39x= 27
x = 27/39 = 9/13
so , y = -5/13 ans.
Anonymous:
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Answered by
376
Answer:
Solve by elimination method……
Step-by-step explanation:
Lets see, we have two equations given by you…
3x – 5y – 4 = 0 or 3x -5y = 4 ……………. (1).
9x = 2y + 7 or 9x -2y = 7 ……………………(2).
Now only focusing on eq. numbered 1 and 2 …
3x – 5y = 4…………………………(1)
9x – 2y = 7 ………………………(2)
Multiply eq. (1) by 3, we get….
3 (3x – 5y = 4) or 9x – 15y = 12……………………. (3).
Now we can easily subtract (2) and (3) to get…..
9x – 2y = 7
- 9x – 15y = 12.
- ______________
- +13 y = -5
Or we get 13 y = -5 or y = -5/13.
Now we substitute the value of Y = -5/13 in equation (1) we get the value of x.
3x – 5(-5/13) = 4
3x +25/13 = 4
39x + 25 = 52
Or 39x = 52 – 25
39x = 27
Or x = 27/39 = 9 / 13
So x = 9/13 and y = -5/13.
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