Math, asked by thakur199251, 6 months ago

3x-5y-4=0 where y= -5/13 find the value of x​

Answers

Answered by ambarkumar1
1

3x – 5y – 4 = 0

y = – 5 / 13

3x – 5 ( – 5 / 13 ) – 4 = 0

3x + 25 / 13 – 4 = 0

3x + ( 25 – 52 ) / 13 = 0

3x – 27/13 = 0

3x = 27/13

x = 27 / ( 13 × 3 )

x = 9 / 13

Answered by SaltyScream
1

Answer:

the answer to your question

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