3x+5y=4,2x+3y=4 using substitution method
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=> 3x + 5y = 4
=> 3x = 4 - 5y
=> x = 4 - 5y / 3 -----(1)
=> 2x + 3y = 4 ------(2)
Substitute equation (1) in (2) ,,,,
=> 2x + 3y = 4
=> 2 ( 4 - 5y / 3 ) + 3y = 4
=> 8 - 10y / 3 + 3y = 4
=> -10y / 3 + 3y = 4 - 8
=> -10y + 9y / 3 = -4
=> -y / 3 = -4
=> -y = -4 × 3
=> -y = -21 ( by cross multiplying )
=> y = 21
Substitute y = 21 in equation (1)
=> x = 4 - 5y / 3
=> x = 4 - 5 × 21 / 3
=> x = 4 - 105 / 3
=> x = 101 / 3
Hope it's helpful .....
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