(3x+5y-4z)² expand using suitable identity
Answers
Answered by
11
Answer:
By using the identity
(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
(3x+5y-4z)²=(3x)²+(5y)²+(-4z)²+2((3x×5y)+(5y×-4z)+ (-4z×3x)
9x²+25y²+16z²+2(15xy-20yz-12xz)
9x²+25y²+16z²+30xy-40yz-24xz
Answered by
1
Answer:
How to solve your problem
(3+5−4)2
Simplify
1
Expand the square
(3+5−4)2
\left(3x+5y-4z\right)^{2}(3x+5y−4z)2
(3+5−4)(3+5−4)
Distribute
(3
Similar questions