3x+5y=9and3x+2y-4=o
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Answer:
3x+5y=9_(1)
3x+2y-4=0_(2)
(1)-(2)
3x + 5y = 9
3x + 2y = 4
(-)__(-)___(-)__
=> 0x + 3y = 5
therefore y = 5/3
substitute y = 5/3 in equation (1)
=> 3x + 5(5/3)=9
=> 3x + 25/3 = 9
=> 9x +25 = 27(by taking lcm and cross multi.)
=> 9x = 27-25
=> 9x= 2
=> x =2/9
therefore
x= 2/9 and y =5/3
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