Question

3x+6/8 - 11x-8/24 +x/3 = 3x/4 - x+7/24 solve this question of chapter linear equation in one variable​

Answer 1

Solution :-

→ (3x + 6)/8 - (11x - 8)/24 + (x/3) = (3x/4) - (x + 7)/24

taking LCM of denominators we get,

→ (9x + 18 - 11x + 8 + 8x)/24 = (3x - x - 7)/24

cancel the same denominator,

→ 17x - 11x + 26 = 2x - 7

→ 6x + 26 = 2x - 7

→ 6x - 2x = (-7) - (26)

→ 4x = (-33)

→ x = (-33/4) (Ans.)

Learn more :-

JEE mains Question :-

https://brainly.in/question/22246812

. Find all the zeroes of the polynomial x4

– 5x3 + 2x2+10x-8, if two of its zeroes are 4 and 1.

https://brainly.in/question/39026698

Answer 2

Answer:

If (3x+6)/(8)-(11x-8)/(24)+(x)/(3)=(3x)/(4)-(x+7)/(24) ,then the value of x is