Question

3x^+6-9=0 find the quadratic equation roots ​

Answer 1

Answer:

9and 3

Step-by-step explanation:

here the roots of the quadratic equation is 9 and 3

Answer 2

sorry this question will not be made from me.

I have a question that solve your question.

root 3

$\sqrt{3x2} + 6 - 9 = 0$

find the positive root of

$sqrt(3x2 + 6) = 9$

Do the square bothsides of the equation

3x²+6=81

3x²=75

Divide both side with 3

3x⅔=75/3

x²=25

Now,

x=sqrt(25)

x=xor =5

But we need positive root ,

therefore,

x=5.

I hope this help you