Question

3x^-6x+2
find the roots plz​

Answer 1

Answer:

Plz find the attachment

hope it helps you

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Answer 2

Answer:

$\huge\underline{ \underline{ \red{your \: \: answer}}}$

Step-by-step explanation:

$\sf\red{using \: quadratic \: equtation = > x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} } \\ \\ \sf\green{ {3x}^{2} - 6x + 2 } \\ \\ \sf\orange{ = = > x = \frac{ - ( - 6)± \sqrt{ { - 6}^{2} - 4 \times 3 \times 2 } }{2 \times 3} } \\ \\ \sf\purple{ = = > \frac{6± \sqrt{36 - 24} }{6} } \\ \\ \sf\blue{ = = > \frac{6±\sqrt{12} }{6} } \\ \\ \sf\purple{ = = > \frac{6±2 \sqrt{3}}{6} } \\ \\ \sf\green{ = = > \frac{3± \sqrt{3} }{3} } \\ \\ \sf\pink{x = = > \frac{{ 3+ \sqrt{3}}}{3}}\\ \\ \sf\red{x = = > \frac{3 - \sqrt{3} }{3} }$

$\large\boxed{ \fcolorbox{green}{violet}{hope \: it \: help \: you}}$