Question

3x-7y +10=0 , y-2x-3=0 solve by substitution method

Answer 1

Hey!!
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3x - 7y + 10 = 0

3x - 7y = - 10--------------(1)

y - 2x - 3 = 0

-2x + y = 3----------------(2)


From eq'n (1)

3x - 7y = -10

=> 3x = -10 + 7y

=> x = - 10 + 7y/3---------------(3)

Substitute eq'n (3) in eq'n (2)

-2x + y = 3

=> -2 (- 10 + 7y)/3 + y = 3

=> 20 - 14y/3 + y = 3

=> 60 -14y + 3y = 9

=> 60 - 11y = 9

=> -11y = 9 - 60

=> -11y = -51

=> y = 51/11.

Putting the value of y in (3)

=> x = - 10 + 7y/3

=> x = -10 + 7 (51/11)/3

=> x = -10 + 357/11/3

=> x = -1110 + 357/11/3

=> x = 247 / 11 / 3

=> x = 3 × 247 / 11

=> x = 741 / 11.

Hence x= 741 /11 and y = 51 /11.

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Hope it will helps you:-)