Question

3x-7y+10=0 y-2x=3 cross multiplication​

Answer 1

GIVEN:

The equations are 3x-7y+10=0 and y-2x=3

TO FIND :

The values of x and y by using the Cross Multiplication Method.

SOLUTION :

Given  equations are 3x-7y+10=0 and y-2x=3

$3x-7y+10=0\hfill (1)$

y-2x=3 can be written as

$-2x+y-3=0\hfill (2)$

Now solving the equations by using the Cross Multiplication Method.

The formula for  Cross Multiplication Method is given by:

For equations $a_1x+b_1y+c_1=0$ and $a_2x+b_2y+c_2=0$

$\frac{x}{b_1c_2-b_2c_1}=\frac{y}{c_1a_2-c_2a_1}=\frac{1}{a_1b_2-a_2b_1}$

$a_1=3$, $b_1=-7$, $c_1=10$, $a_2=-2$, $b_2=1$ and  $c_2=-3$

Substitute the values in formula,

$\frac{x}{-7(-3)-(1)(10)}=\frac{y}{(10)(-2)-(3)(-3)}=\frac{1}{1(3)-(-2)(-7)}$

$\frac{x}{21-10}=\frac{y}{-20+9}=\frac{1}{3-14}$

$\frac{x}{11}=\frac{y}{-11}=\frac{1}{-11}$

Now equating $\frac{x}{11}=\frac{1}{-11}$

$x=\frac{-1}{11}\times 11$

∴ x=-1

Now equating $\frac{y}{-11}=\frac{1}{-11}$

$y=\frac{-1}{11}\times (-11)$

∴ y=1

∴ the values are x=-1 and y=1.

Answer 2

Answer:

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