3x +7y=10 and 2x+y=3 (elimination method)
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Answer :-
3x-7y=-10......(1)
3x-7y=-10......(1)
-2x+y=3........(2)
eq (2) can be written as 2x-y=-3
multiply Eq (1) with 2
multiply Eq (2) with 3
then subtract eq( 1) and eq(2) after multiplication
resultant value
then we get -11y=-11
y=-11/-11
==> y=1
substitute y value in eq(1)
then ,
3x-7*1 = - 10
3x-7= -10
3x= -10+7
10+73x= -3
==> x=-1
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