Math, asked by vashudevyadav143, 10 months ago

3x+7y+11=0 and 9x+21y+3=0 By crossmulplication method

Answers

Answered by jsrinu9848

Answer:

Step-by-step explanation:

3x+7y+11=0 9x+21y+3=0

x=0 x=0

3(0)+7y +11 =0 21y+3=0

7y+11 =0 21y=-3

7y=-11 y=-3/21

y=-11/7 y= 0.142857

y= -1. 571428 y=0

y=0 9x+3=0

3x+11=0 9x=-3

3x=-11 x=-3/9

x=-11/3 x= 0.333.....

x= -3.666...

Previous Question

Next Question

Similar questions

Math, 5 months ago

Science, 5 months ago

Social Sciences, 5 months ago

History, 10 months ago

Math, 10 months ago

Just increase ur points ${ { { { { { { { { { { \sqrt{ \sqrt[ | < \leqslant \geqslant | ]{?} } \times \frac{?}{?} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{?}$ ...

Math, 1 year ago

Biology, 1 year ago

English, 1 year ago