3x+7y=15,5x-129=23y
by cross multiplication
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Answered by
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Answer:
x=-39/13
y=12
Step-by-step explanation:
3x+7y=15--------1
5x-129=23y---------2
5×3x+7y=15
3×5x-23y=129
15x+35y=75
15x-69y=387
_ +. -
________________
104y=-312
y=-312/104
y=-39/13
substitute y=-39/13 in equation 1
3x+7y=15
3x+7(-39/13)=15
3x-21=15
3x=15+21
x=36/12
x=12
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