3x+7y=2
6x-5y=4
solve by elimination method
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Answer:
3x+7y=2
6x-5y=4
x=2/3 - 7y/3
6x-5y=4
6(2/3-7y/3)-5y=4
4-19y=4
19y = 0
so y = 0
so 3(2/3-7y/3)=2
so 2-7y=2
again 7y=0
so value of x is 1 and y is 0
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