Question

(3x + 7y): (2x + 5y)​

Answer 1

Answer:

Simplifying

(2x + -5y)(3x + -7y) = 0

Multiply (2x + -5y) * (3x + -7y)

(2x * (3x + -7y) + -5y * (3x + -7y)) = 0

((3x * 2x + -7y * 2x) + -5y * (3x + -7y)) = 0

Reorder the terms:

((-14xy + 6x2) + -5y * (3x + -7y)) = 0

((-14xy + 6x2) + -5y * (3x + -7y)) = 0

(-14xy + 6x2 + (3x * -5y + -7y * -5y)) = 0

(-14xy + 6x2 + (-15xy + 35y2)) = 0

Reorder the terms:

(-14xy + -15xy + 6x2 + 35y2) = 0

Combine like terms: -14xy + -15xy = -29xy

(-29xy + 6x2 + 35y2) = 0

Solving

-29xy + 6x2 + 35y2 = 0

Solving for variable 'x'.

Factor a trinomial.

(2x + -5y)(3x + -7y) = 0

Answer 2

Answer:

$6x^{2} +29 + 35x^{2}$

Step-by-step explanation:

  (3x + 7y)(2x + 5y)

∴ 3x(2x + 5y) +7y(2x + 5y)

∴ $6x^{2}$ + 15xy + 14xy + $35x^{2}$

∴  $6x^{2}$ + 29xy + $35x^{2}$

hope it's helpful

please mark me as a brainliest