Math, asked by Nav4907, 1 year ago

(3x-7y-z)whole square

Answers

Answered by Pseudo
1
=9x^2+49y^2+z^2+2(3x)(-7y)+2(-7y)(-z)+2(-z)(3x)
solve this equation!
Answered by NUISANCE
5
=(3x-7y)^2 + (z)^2 - 2(3x-7y)(z)
=9x^2 + 49y^2 - 2(3x)(7y) +(z)^2 - 6xz + 15yz
= 9x^2 + 49y^2 + z^2 - 42xy -6xz + 15yz
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