(3x-8)/(2x-11) = (3x+11)/(2x+8)
Answers
Answered by
0
Answer:
Given (2x+7)/5−(3x+11)/2=(2x+8)/3−5
Now by taking L.C.M for 2 and 5 is 10
15(2(2x+7)−5(3x+11))/10=(2x+8)/3−5
By transposing the above equation we can write as
33x−20x=123−70
Again by transposing
X=−53/53
x=−1
Answered by
2
X = -3
answer = -3.
hope it works..!!
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