Math, asked by manashberiwal776, 9 months ago

(3x-8) (3x+2)-(4x-11) (2x+1)=(x-3) (x+7) find x

Answers

Answered by priya2106kaushik
0

Answer:

4

(3x-8) (3x+2)-(4x-11) (2x+1)=(x-3) (x+7)

9x^2 + 6x-24x-16-8x^2-4x-4x+22x+11= x^2 +7x-3x-21

x^2-5= x^2+4x-21

4x=16

x=4

Answered by JaneShadders
0

Answer:

4

Step-by-step explanation:

(3x-8) (3x+2)-(4x-11) (2x+1)=(x-3) (x+7)

9x^2 +6x-24x-16-[8x^2+4x-22x-11]=x^2+4x-21

9x^2 +6x-24x-16-8x^2-4x+22x+11=x^2+4x-21

x^2-5=x^2+4x-21

16=4x

x=16/4

x=4

Hope this helps, please mark it the brainliest!

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