Question

3x [8y➗4 - 6{x - (5x - 3y - 2x)}]. (Note: solve 3y - 2x first!)

Answer 1

sorry no answer..

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Answer 2

Given :- solve :- 3x[8y ÷ 4 - 6{x - (5x - 3y - 2x)}].

Solution :-

→ 3x[8y ÷ 4 - 6{x - (5x - 3y - 2x)}]

solving "round bracket" ( ) first,

→ 3x[ 8y ÷ 4 - 6{ x - (3x - 3y)}]

sign will change after opening of bracket ,

→ 3x[ 8y ÷ 4 - 6{ x - 3x + 3y}]

solving "curly bracket" { } now,

→ 3x[8y ÷ 4 - 6{3y - 2x}]

again, changing sign,

→ 3x[8y ÷ 4 - 18y + 12x]

now, solving , "square bracket" [ ] , first we will solve ÷ ,

→ 3x[ (8y/4) - 18y + 12x]

→ 3x[2y - 18y + 12x]

→ 3x[12x - 16y]

→ 3x * 12x - 3x * 16y

→ (48x² - 48xy) (Ans.)

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