(3x+9)power2=? maths problem
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= (3x) ^2+(9) ^2+2× 3x × 9 [(a+b) ^2= a^2+b^2+2×a×b) ]
= 9x^2+81+54x
= 9x^2+81+54x
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Answer:
Step-by-step explanation:
Here identity used: (a+b)²= a² + b² + 2ab
(3x+9)² = (3x) ²+ 9²+ 2×3x ×9
= 9x² + 81 + 54x
9x² + 54x +81
Dividing by 9
= x²+6x+9
= x²+3x+3x+9
=x(x+3)+3(x+3)
=(x+3)(x+3)
x+3=0. ; x+3=0
x=-3. ; x = -3
Hope it help u
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