Question

√3x+9 + x = 3 solve for x

Answer 1

Answer:

$\sqrt{3} x + 9 + x = 3\\ \implies \: \sqrt{3} x + 9 + x - 3 = 0 \\ \implies \: \sqrt{3} x + x + 9- 3 = 0 \\ \implies \: \sqrt{3} x + x + 9- 3 = 0 \\\implies ( \sqrt{3} + 1)x + 6 = 0 \\ \implies ( \sqrt{3} + 1)x = - 6 \\ \implies x = \frac{ - 6}{ \sqrt{3} + 1} \\ \implies x = \frac{ - 6}{ \sqrt{3} + 1} \times \frac{ \sqrt{3} - 1 }{ \sqrt{3} - 1} \\ \implies x = \frac{ - 6( \sqrt{3} - 1) }{( \sqrt{3}) ^{2} - (1)^{2} } \\ \implies x = \frac{ - 6( \sqrt{3} - 1) }{3 - 1 } \\ \implies x = \frac{ - 6( \sqrt{3} - 1) }{2} \\ \implies x = - 3( \sqrt{3} - 1)$