Question

3x+9y/xy=11,6x+3y/xy=7,X is not equal to 0 Y ia not equal to 0​

Answer 1

Answer:

x = 1 , y = 3/2

Solution:

Here ,

The equations are ;

(3x + 9y)/xy = 11 ------(1)

(6x + 3y)/xy = 7 --------(2)

Eq-(1) can be rewritten as ;

=> (3x + 9y)/xy = 11

=> 3x/xy + 9y/xy = 11

=> 3/y + 9/x = 11

=> 9/x + 3/y = 11 --------(3)

Eq-(2) can be rewritten as ;

=> (6x + 3y)/xy = 7

=> 6x/xy + 3y/xy = 7

=> 6/y + 3/x = 7

=> 3/x + 6/y = 7 ---------(4)

Now,

Multiplying eq-(3) by 2 , we have ;

=> 2•(9/x + 3/y) = 11•2

=> 18/x + 6/y = 22 ----------(5)

Now,

Subtracting eq-(4) from eq-(5) , we get ;

=> (18/x + 6/y) - (3/x + 6/y) = 22 - 7

=> 18/x + 6/y - 3/x - 6/y = 15

=> 18/x - 3/x = 15

=> (18 - 3)/x = 15

=> 15/x = 15

=> x = 15/15

=> x = 1

Now,

Putting x = 1 in eq-(4) , we get ;

=> 3/x + 6/y = 7

=> 3/1 + 6/y = 7

=> 3 + 6/y = 7

=> 6/y = 7 - 3

=> 6/y = 4

=> y = 6/4

=> y = 3/2

Hence ,

x = 1 , y = 3/2

Answer 2

Answer:

Hope it works................................™✌️✌️