Question

3x +aky=2 &22 +5941=0
are parallel to each other, theo
value of B​

Answer 1

Answer:

Condition for the lines to be parallel is

a  

2

​

 

a  

1

​

 

​

=  

b  

2

​

 

b  

1

​

 

​

 



=  

c  

2

​

 

c  

1

​

 

​

 

Here the equations are

3x+2ky=2 and 2x+5y+1=0

So, a  

1

​

=3,b  

1

​

=2k,c  

1

​

=−2 and a  

2

​

=2,b  

2

​

=5,c  

2

​

=1

∴  

a  

2

​

 

a  

1

​

 

​

=  

2

3

​

,  

b  

2

​

 

b  

1

​

 

​

=  

5

2k

​

 and  

c  

2

​

 

c  

1

​

 

​

=  

1

−2

​

=−2

∴  

5

2k

​

=  

2

3

​

 

∴k=  

4

15

​

Step-by-step explanation: