Question

3x = cot A and (3/x) = cosec A. Find 3[( 1 / x^2) – (x^2)]

Answer 1

Answer:

Since it is given that 3x=cosec theta and 3/x=cot theta

so,x=cosec theta/3 & 1/x=cot theta/3

so,3(cosec theta^2/9 - cot^2/9)

3[1/9(cosec theta^2 - cot theta^2). -(1)

as we know that 1 + cot theta^2=cosec theta^2

1=cosec theta^2 - cot theta ^2. -(2)

putting value of (2) in (1)

1/3(1)

1/3

Step-by-step explanation:

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