Question

3x cube-4x square -12 x+16 hit and trial method

Answer 1

Answer:

x = 2

Step-by-step explanation:

$3 {x}^{3} - 4 {x}^{2} - 12x + 16 = 0$

if , x = 1 , we get

$3 \times {1}^{3} - 4 \times {1}^{2} - 12 \times 1 + 16$

$3 - 4 - 12 + 16 \: = 19 - 16 \: = 3$

3 is not equal to 0

if , x = 2 , we get

$3 \times {2}^{3} - 4 \times {2}^{2} - 12 \times 2 + 16$

$3 \times 8 - 4 \times 4 - 24 + 16$

$24 - 16 - 24 + 16$

$24 - 24 + 16 - 16$

$= 0$