Question

3x cube-6x square+3x-7/9÷3x-4​

Answer 1

or either simplify it first and then solve

Answer 2

$x^{2}-\frac{2 x}{3}+\frac{1}{9}+\frac{-\frac{1}{3}}{3 x-4}$

Step-by-step explanation:

Check explanation in attachment

To learn more

i)Find the remainder when 3x^3-6x^2 +3x-7/9 is divided by 3x-4

https://brainly.in/question/3937180

ii)Find the reminder when 3x cube- 6x square + 3x - 7/9 is divided by 3x-4​

https://brainly.in/question/14772630