Question

3x cube minus x square - 3 x + 1 factorise
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Answer 1

Answer:

$3x^3-x^2-3x+1\\\\= x^2(3x-1)-(3x-1)\\\\= (3x-1)(x^2-1)\\\\= (3x-1)(x-1)(x+1)$

$a^3-2\sqrt{2}b^3\\\\=a^3-(\sqrt{2}b)^3\\\\Now\\\\(x-y)^3=x^3-y^3-3xy(x-y)\\\\x^3-y^3=(x-y)^3+3xy(x-y)\\\\x^3-y^3=(x-y)(x^2+y^2+xy)\\\\Now \\\\x=a\\\\y=\sqrt{2}b\\\\a^3-(\sqrt{2}b)^3\\\\=(a-\sqrt{2}b)(a^2+2b^2+\sqrt{2}ab)$

HOPE IT HELPS

Answer 2

Answer:

3x

m

Step-by-step explanation:

$3x {3 - x { - 3x + 1}^{2} }^{?}$

$x {(3x - 1) - 1(3x - 1)}^{2}$

$(x { - 1)(3x - 1)}^{2}$

$x = \sqrt{1}$

$x = 1 \div 3$