Question

3x square - 10x+3 factorise by splitting the middle term​

Answer 1

Answer:

$\huge\underline{ \underline{ \red { \bigstar:)your \: \: \: answer \bigstar(: }}}$

Step-by-step explanation:

$\bf\orange{ \mapsto: {3x}^{2} - 10x + 3 = 0} \\ \\ \bf\pink{ \mapsto: {3x}^{2} - (9x + x) + 3 = 0} \\ \\ \bf\green{ \mapsto: {3x}^{2} - 9x - x + 3 = 0 } \\ \\ \bf\purple{ \mapsto: 3x(x - 3) - 1(x - 3) = 0 } \\ \\ \bf\orange{ \boxed{ \mapsto: \bigstar(3x - 1)(x - 3) = 0 \bigstar}} \\ \\ \bf\green{ \implies:3x - 1 = 0 } \\ \bf\blue{ \mapsto:x = \frac{1}{3} } \\ \\ \bf\red{ \implies: x - 3 = 0} \\ \bf\pink{ \mapsto: x = 3} \\ \\ \large\boxed{ \fcolorbox{red}{yellow}{(: hope \: it \: help \: you( : }}$

Answer 2

Answer:

x = 3 or 1/3

Step-by-step explanation:

3x^2 - 10x + 3 = 0

• => first step

take 3 from 3x^2 & 3 => 3×3 = 9

• second step

prime factors of 9 => 3,3,1

• third step

arrange 3,3,1 such that on addition or subtraction it gives -10 ( bcoz -10x is given)

=> -9 - 1 = -10

now

factorise

=> 3x^2 -10x + 3 = 0

=> 3x^2 - 9x - x + 3 = 0

=> 3x( x - 3) - 1 (x - 3) = 0

=> (3x - 1) (x-3) = 0

=> (3x - 1) = 0 or (x-3) = 0

=> 3x = 0+1 or x = 1/3 ( from 1st expression)

&

x = 0+3 => x = 3 (from 2nd expression)