3x square + 10x +8 can you explain me how to solve it
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Answer:
The answer is S={2,43}
Explanation:
We compare this equation to
ax2+bx+c=0
3x2−10x+8=0
The discriminant is
Δ=b2−4ac=100−4⋅3⋅8=100−96=4
As, Δ>0, there are 2 real roots
x=−b±√Δ2a
x1=10+26=2
x2=10−26=86=43
The answer is S={2,43}
Explanation:
We compare this equation to
ax2+bx+c=0
3x2−10x+8=0
The discriminant is
Δ=b2−4ac=100−4⋅3⋅8=100−96=4
As, Δ>0, there are 2 real roots
x=−b±√Δ2a
x1=10+26=2
x2=10−26=86=43
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the values of x are -4/3 and -2
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